API reference
For this section, I assumed that the method in the code sample is part of a class NeedlesInHaystack
.
Class: NeedlesInHaystack
This class provides functionality to search for multiple needle strings within a single haystack string and outputs the frequency of each needle’s occurrence.
Method: findNeedles
-
Type:
public static
-
Parameters:
-
String haystack
: The text within which to search for the needles. -
String[] needles
: An array of strings representing the words (needles) to be counted in the haystack.
-
-
Returns:
void
(prints results to the console) -
Usage: This method prints the number of times each string in the
needles
array appears in thehaystack
string.
Example
String haystack = "Google Cloud provides APIs to use Google's ML/AI capabilities.";
String[] needles = {"Google", "API", "documentation", "AWS", "ML/AI"};
new NeedlesInHaystack().findNeedles(haystack, needles);
Output
Google: 2
API: 0
documentation: 0
AWS: 0
ML/AI: 1
Suggestions for code improvement
After reviewing the code sample, I have the following suggestions for improvement:
-
Limit the number of
needles
: The current code restricts the length of theneedles
array to five. If this is a strict requirement, modify the message in the print statement within theif
block to"Use a maximum of five words!"
. This provides clearer guidance than"Too many…"
. -
Assign
needles.length
to a variable: Storeneedles.length
in a variable to eliminate repeated evaluation of the same expression. This also improves memory efficiency. -
Optimize
haystack.split()
: Move the following statement outside of the loop:String[] words = haystack.split("[ \"\'\t\n\b\f\r]", 0);
. Thewords
array does not change with each iteration, so splitting thehaystack
only once is more efficient. -
Improve readability: In the third for loop, use
k
as the iterator variable, asi
andj
are already in use in nearby loops. -
Consider using a
HashMap
: To store the frequency of each needle, consider using aHashMap
. This provides a more flexible and efficient way to handle the counting, especially if you want to return key-value pairs or add further functionality later.
Revised code sample
Here is the revised code, which incorporates the suggested improvements for efficiency and clarity:
public class NeedlesInHaystack {
public static void findNeedles(String haystack, String[] needles) {
// Store the length of the needles array in a variable
int needlesLength = needles.length;
// Split the haystack string once
String[] words = haystack.split("[ \"\'\t\n\b\f\r]", 0);
// Create an array to store the frequency counts
int[] countArray = new int[needlesLength];
// Iterate through the needles and count their occurrences
for (int i = 0; i < needlesLength; i++) {
for (int j = 0; j < words.length; j++) {
if (words[j].compareTo(needles[i]) == 0) {
countArray[i]++;
}
}
}
// Print the results
for (int k = 0; k < needlesLength; k++) {
System.out.println(needles[k] + ": " + countArray[k]);
}
}
public static void main(String[] args) {
// Hard-coded values for demonstration
// Ideally, values should be received from standard input
String haystack = "Google Cloud provides APIs to use Google's ML/AI capabilities.";
String[] needles = {"Google", "API", "documentation", "AWS", "ML/AI"};
findNeedles(haystack, needles);
}
}
Sample output
Google: 2
API: 0
documentation: 0
AWS: 0
ML/AI: 1